Capacitor Energy Calculator

E = ½ C V². 4700 µF at 50 V stores 5.875 J.

Calculator

PASS5.875 J0.001632 Wh

E = ½ C V². Voltage may be negative; energy uses V². Optional R reports τ = R C.

E
5.875 J
Wh
0.001632 Wh
Q
0.2350 C
  • Pass Stored energy: E = ½ C V² = 5.87500 J

Formula

Stored energy

E=12CV2 E = ½ C V²

Charge

Q=CV Q = C V

Variables

Symbol Meaning Unit Typical range Precision Default
C Capacitance F ≥ 0 pF 4 sig 4.7 mF
V Voltage V — 4 sig 50 V
R Resistance (optional τ) Ω — 4 sig
E Stored energy J — 4 sig —
EWh Stored energy Wh — 4 sig —
Q Charge — — 4 sig —

Worked example

4700 µF at 50 V

Input Value
C · Capacitance 4.7 mF
V · Voltage 50 V
Output Value
E · Stored energy 5.875 J
EWh · Stored energy 0.001632 Wh
Q · Charge 0.235

100 µF at 5 V

Input Value
C · Capacitance 100 µF
V · Voltage 5 V
Output Value
E · Stored energy 1.25 mJ
Q · Charge 0.0005

How it works

The energy in a capacitor is the thing you feel when a bulk cap dumps into a screwdriver. It is also the number you need before you pick a bleeder.

Enter C and V. Optional R adds the time constant. For a full 1τ–5τ table, open the RC time constant calculator; for a safety dump toward a labelled Vsafe, open the discharge calculator.

Pitfalls

  • Forgetting that energy scales with V² — 2× voltage is 4× energy.
  • Reading a millijoule figure as joules when comparing to a dump resistor.
  • This is stored energy, not a battery watt-hour rating.

FAQ

How much energy in 4700 µF at 50 V?

½ × 0.0047 × 50² = 5.875 J.

Why does negative voltage still show energy?

E uses V². The sign sits on the charge Q = C V.

Can I also get τ?

Yes. Optional R reports τ = R C from the same engine.

Is Wh useful here?

Only as a unit conversion. These energies are small compared with a cell.

Related

Sources