Current Divider Calculator

Ik = I · (1/Rk) / Σ(1/Ri). 1 A into 100 Ω ∥ 200 Ω is 666.7 mA and 333.3 mA.

Calculator

PASS666.67 mA / 333.33 mAReq 66.67 Ω

Ik = I · (1/Rk) / Σ(1/Ri). R = 0 is a short and is an error — this page does not split current among ideal shorts.

I1
666.67 mA
I2
333.33 mA
Req
66.67 Ω
  • Pass Parallel equivalent: Req = 66.6667 Ω, N = 2

Formula

Branch current

Ik=I1/RkΣ1/Ri Ik = I · (1/Rk) / Σ(1/Ri)

Parallel equivalent

Req=1Σ1/Ri Req = 1 / Σ(1/Ri)

Shorted branch

Rk≠0 R = 0 is a short and is an error

Variables

Symbol Meaning Unit Typical range Precision Default
I Total current A — 4 sig 1 A
Rk Branch resistors Ω ≥ 0 mΩ R = 0 is rejected 4 sig 100, 200
Ri Branch i resistance Ω — 4 sig —
Req Parallel equivalent Ω — 4 sig —
N Branches — — 4 sig —
Isum Sum of branch currents A — 4 sig —
Ik Branch k current A — 4 sig —
I1 Branch 1 current A — 4 sig —
I2 Branch 2 current A — 4 sig —
I3 Branch 3 current A — 4 sig —
P1 Branch 1 power W — 4 sig —
P2 Branch 2 power W — 4 sig —
P3 Branch 3 power W — 4 sig —

Worked example

1 A into 100 Ω ∥ 200 Ω

Input Value
I · Total current 1 A
Rk · Branch resistors 100, 200
Output Value
I1 · Branch 1 current 666.7 mA
I2 · Branch 2 current 333.3 mA
Req · Parallel equivalent 66.67 Ω
P1 · Branch 1 power 44.44 W
P2 · Branch 2 power 22.22 W

100 mA into 1 k / 2.2 k / 4.7 k

Input Value
I · Total current 100 mA
Rk · Branch resistors 1000, 2200, 4700
Output Value
I1 · Branch 1 current 59.98 mA
I2 · Branch 2 current 27.26 mA
I3 · Branch 3 current 12.76 mA
Req · Parallel equivalent 599.8 Ω

How it works

Current prefers the smaller resistor. Write each branch as a conductance, normalise, and multiply by I. A typed 0 Ω is a short, not a trick to dump all current into one number — the page refuses it.

Pitfalls

  • Entering 0 Ω and expecting an equal split. An ideal short has no finite branch current; this page errors.
  • Forgetting that wire resistance is the real limit once a branch is a short.
  • Using this AC on inductors — it is a DC resistor model.

FAQ

How does 1 A split between 100 Ω and 200 Ω?

0.667 A in 100 Ω and 0.333 A in 200 Ω.

Why is R = 0 an error?

Ik = I · (1/Rk)/Σ(1/Ri) divides by zero. Splitting current among ideal shorts has no finite answer.

Can I reverse the current sign?

Yes. Negative I just reverses every branch; power stays positive.

How many branches can I enter?

There is no hard cap on this page. Ten is a comfortable layout limit.

Related

Sources